http://img193.imageshack.us/img193/4...00122at428.png

I blanked on how to solve this. I thought i take the seventh root and put it inside, so it would be (x)^7/2 then differentiate ...but i was wrong. Any takers? Thanks!

Printable View

- Jan 22nd 2010, 01:39 PMEvan.Kimiadifferentiate this equation...
http://img193.imageshack.us/img193/4...00122at428.png

I blanked on how to solve this. I thought i take the seventh root and put it inside, so it would be (x)^7/2 then differentiate ...but i was wrong. Any takers? Thanks! - Jan 22nd 2010, 01:40 PMLord Darkin
Wouldn't it just be (1/(seventh root of x)) * Chain rule?

- Jan 22nd 2010, 02:31 PMdrumist

You can use chain rule. - Jan 22nd 2010, 02:37 PMdrumist
Or even easier:

- Jan 22nd 2010, 03:16 PMEvan.Kimia
It was that part i forgot. thanks.

- Jan 23rd 2010, 04:51 AMSeulementrienanswer
f(x)=(1/7)lnx

so f'(x)=1/7x