Thread: Double-check this limit please

Can someone double-check my work here? Thanks, if you can.



Put x to the denominator to use L'Hopital's rule, etc. Applied chain rules, etc.



Thus, if x goes to infinity, the above is sin(0) = 0. Final Answer: Zero

Yes, it's okay, but you don't need that rule, you can turn that limit into a known one with a simple substitution.

Oh, really? What is this substitution?

tx=1

so itequals to lim [(1-cost)/t]
t->0