1. $\displaystyle \int x^2sin2x dx$
2.$\displaystyle \int (x+3)/(x+1) $
Hint: integration by parts: $\displaystyle u = x^2, ~dv = \sin 2x dx$ (you will have to do integration by parts twice.
Hint: Note that this is $\displaystyle \int \frac {x + 1 + 2}{x + 1}~dx = \int \left( 1 + \frac 2{x + 1} \right)~dx$2.$\displaystyle \int (x+3)/(x+1) $