1. ## Double Integral

HELLO
Problem:
Evaluate $\displaystyle \int_0^4 \int_{\sqrt x}^{2} e^{-y^3} dy dx$
Surely, I will reverse the order to :
$\displaystyle \int_0^2 \int_{y^2}^4 e^{-y^3} dx dy$
I want only to check the new integral
Is the upper/lower limits correct??

and which one is correct : "upper" or "uper" ?

2. Note x varies from 0 to y^2 as y varies from 0 to 2

See attachment for graph