Im having trouble with this problem. Lim (x approaches INF) of (8x+4)/(7x-3) Can anyone help? Thanks!
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Hi You can write $\displaystyle \frac{8x+4}{7x-3} = \frac{x(8+\frac{4}{x})}{x(7-\frac{3}{x})} = \frac{8+\frac{4}{x}}{7-\frac{3}{x}}$
Thanks you!
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