Let be function differentiable on and satisfy conditions Prove that .
Follow Math Help Forum on Facebook and Google+
Let thus the only thing we need to prove is that We have that but given we get that which is the same as thus then for We proved a stronger result, given differentiable.
Yes, this is it. Congratulations for nice solution. And little correction: from you can't conclude but just, by integration, that , and than from that .
Originally Posted by Krizalid Let thus the only thing we need to prove is that We have that but given we get that which is the same as thus then for We proved a stronger result, given differentiable. assuming for just g(x)? Doesnot it mean that the proof is only for g(x)? please clarify and comment.
Originally Posted by Pulock2009 assuming for just g(x)? Doesnot it mean that the proof is only for g(x)? please clarify and comment.
Originally Posted by ns1954 Yes, this is it. Congratulations for nice solution. And little correction: from you can't conclude but just, by integration, that , and than from that . Actually by definite integration I conclude that, so there's no problem.
View Tag Cloud