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Thread: arctan question

  1. Jan 21st 2010, 07:06 AM #1
    transgalactic
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    arctan question

    -\frac{\pi}{4}=arctan(\frac{\frac{-2L}{3}}{R})\\
    why it equals
    \frac{\frac{-2L}{3}}{R}=-1
    ?
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  2. Jan 21st 2010, 07:07 AM #2
    General
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    Quote Originally Posted by transgalactic View Post
    -\frac{\pi}{4}=arctan(\frac{\frac{-2L}{3}}{R})\\
    why it equals
    \frac{\frac{-2L}{3}}{R}=-1
    ?
    By taking "tan" for the both sides of the first equation.
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  3. Jan 21st 2010, 07:11 AM #3
    drumist
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    I'm not sure what you are asking.

    \arctan(x)=-\pi/4 has just one solution, which is x=-1.
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