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Thread: arctan question

  1. #1
    MHF Contributor
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    arctan question

    $\displaystyle -\frac{\pi}{4}=arctan(\frac{\frac{-2L}{3}}{R})\\$
    why it equals
    $\displaystyle \frac{\frac{-2L}{3}}{R}=-1$
    ?
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  2. #2
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    Quote Originally Posted by transgalactic View Post
    $\displaystyle -\frac{\pi}{4}=arctan(\frac{\frac{-2L}{3}}{R})\\$
    why it equals
    $\displaystyle \frac{\frac{-2L}{3}}{R}=-1$
    ?
    By taking "tan" for the both sides of the first equation.
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  3. #3
    Senior Member
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    I'm not sure what you are asking.

    $\displaystyle \arctan(x)=-\pi/4$ has just one solution, which is $\displaystyle x=-1$.
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