# Math Help - limit as x -> pi in [[sinx]]

1. ## limit as x -> pi in [[sinx]]

Ok so the greatest integer function. What I don't get is why the limit as x->pi of [[sinx]] from the left is 0 but as it approaches pi from the right it is -1? Something I'm missing about the graph because I looked up the graph of sin[x] if that even is the same as [sinx] and it just looks like the limits are both going to 1. Stumped...

2. Originally Posted by BugzLooney
Ok so the greatest integer function. What I don't get is why the limit as x->pi of [[sinx]] from the left is 0 but as it approaches pi from the right it is -1? Something I'm missing about the graph because I looked up the graph of sin[x] if that even is the same as [sinx] and it just looks like the limits are both going to 1. Stumped...

$0<\sin x<1$ for $\frac{\pi}{2} and thus $[\sin x]=0$ there, but $-1<\sin x<0$ for $\pi and thus $[\sin x]=-1$ there ...

Tonio