And it's asking to find the interval of [A,B].
I know how to find the inverse of the function, and I also know that the range of the function f(x) would be the domain of the inverse. However I don't know how to find that out.
And it's asking to find the interval of [A,B].
I know how to find the inverse of the function, and I also know that the range of the function f(x) would be the domain of the inverse. However I don't know how to find that out.
I took the difficult route assuming f(x) = 1/(4x) -4
The problem is you have a singularity at x = 0
For [-3,0) the range of f is (-inf, f(-3)) = (-inf,-49/12) = domain of f^(-1)
For (0,1] the range is (f(1),infinity)=(f(-15/4),infinity) = domain of f ^(-1)
Domain of f^(-1) is the union of the 2 domains
See graphs in attachment
it all if you have the simple linear function!!
i must say i myself find the notation vague, because i have seen posters interpret it both ways. i would much prefer if parentheses are used for clarification: (1/4)x as opposed to 1/(4x) and forget typing things like 1/4x. Of course, the better option is for posters to learn LaTeX