lim ln|x -2|

x--> 2

I'm not quite sure what to do. I know that I can't take the ln of a negative number and I can't take the ln of 0. When I evaluate the limit for x = 2, my function is undefined and so is my limit (did I say this correctly?).

Am I correct?

Even if I manipulate the function knowing the definition of absolute value i.e. |x| = x^2/2 i still get

ln(x-2)^(2/2)

ln(x-2)^(1/2) + ln(x-2)^(1/2)