Please help f(x)= 1/2x - 1/3x^2 =(2x)^-1 -(3x)^-2 f ' =(-2x)^-2 + (6x)^-3 =-2/x^2 + 6/x^-3 This is as far as I can get, the finished answer should be 4-3x/6x^3 Can you show me how to finish it please? Thanks
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Originally Posted by wolfhound Please help f(x)= 1/2x - 1/3x^2 =(2x)^-1 -(3x)^-2 f ' =(-2x)^-2 + (6x)^-3 =-2/x^2 + 6/x^-3 This is as far as I can get, the finished answer should be 4-3x/6x^3 Can you show me how to finish it please? Thanks For clarification: Do you mean f(x)= 1/2*x - 1/3*x^2 or f(x)= 1/(2x) - 1/(3x^2) or f(x)= 1/(2x) - 1/((3x)^2)
Originally Posted by earboth For clarification: Do you mean or f(x)= 1/(2x) - 1/((3x)^2) Hello, this one please help
you can finish the algebra grunt work
Originally Posted by skeeter you can finish the algebra grunt work I dont know how to finish it! someone help please
Originally Posted by wolfhound I dont know how to finish it! someone help please Take skeeter's result: 1. Expand the terms at the RHS. Cancel if possible. 2. Determine a common denominator. Transform the fractions such that they have the same denominator. Collect like terms in the numerator. First step: Next steps for you.
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