Please help
f(x)= 1/2x - 1/3x^2
=(2x)^-1 -(3x)^-2
f ' =(-2x)^-2 + (6x)^-3
=-2/x^2 + 6/x^-3
This is as far as I can get, the finished answer should be 4-3x/6x^3
Can you show me how to finish it please? Thanks
Take skeeter's result:
1. Expand the terms at the RHS. Cancel if possible.
2. Determine a common denominator. Transform the fractions such that they have the same denominator. Collect like terms in the numerator.
First step:
$\displaystyle
f'(x) = -\frac{2}{(2x)^2} + \frac{6}{(3x)^3} = -\frac{1}{2x^2}+\frac{2}{9x^3}
$
Next steps for you.