evaluate this impossible integral
$\displaystyle \int_0^1\int_{3y}^3 e^{x^2}dxdy$
i think there's some way to rearrange this to make it possible, but i don't know how
Reverse the order of integration.
Looking at the limits on the integration we have
$\displaystyle 0 \leq y \leq 1$ and $\displaystyle 3y \leq x \leq 3$.
Some rearrangement gives
$\displaystyle 0 \leq y \leq \frac{1}{3}x$ and $\displaystyle 0 \leq x \leq 3$.
So the integral becomes
$\displaystyle \int_0^3{\int_0^{\frac{1}{3}x}{e^{x^2}\,dy}\,dx}$