Find the surface area

$\displaystyle y=Tanx$ limits of $\displaystyle x=0$ and $\displaystyle x=\frac{\pi}{4}$ rotated about the x-axis

$\displaystyle \frac{dy}{dx} = Sec^2x$

$\displaystyle S=\int 2\pi Tanx\sqrt{1+(Sec^2x)^2}dx$

After this step I'm lost. This is the first problem in this section involving trig so I don't think I'm seeing something clearly. I try and relate $\displaystyle Sec^2x$ to $\displaystyle 1+Tan^2x$ but I don't really think that does anything.