find the area of the region bounded by r = 3 + 2sin(theta)

I know the formula to use is A = 1/2 B int A r^2 d theta

where B and A are limits. for the intergral (int)

i have supported work for 2 * 1/2 int(3 + 2 sin(theta))^2 d theta

equation:http://img402.imageshack.us/img402/370/untitledis3.png

am i missing work for the limits?

why am i multiplying by 2?

please help.