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Math Help - find the area of the region bounded..

  1. #1
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    find the area of the region bounded..

    find the area of the region bounded by r = 3 + 2sin(theta)

    I know the formula to use is A = 1/2 B int A r^2 d theta

    where B and A are limits. for the intergral (int)

    i have supported work for 2 * 1/2 int(3 + 2 sin(theta))^2 d theta

    equation:http://img402.imageshack.us/img402/370/untitledis3.png

    am i missing work for the limits?

    why am i multiplying by 2?

    please help.
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  2. #2
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    Hello, rcmango!

    Find the area of the region bounded by: .r .= .3 + 2sinθ

    I know the formula to use is: .A .= . ∫ r dθ

    I have: .A .= .2 * ∫ (3 + 2sinθ) dθ

    Am i missing work for the limits? . Of course!
    Why am i multiplying by 2?
    You could integrate from 0 to 2π, but look at your sketch.
    . . The graph is symmetric to the "y-axis".

    You can integrate from -π to π and multiply by 2.

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