find the area of the region bounded by r = 3 + 2sin(theta)
I know the formula to use is A = 1/2 B int A r^2 d theta
where B and A are limits. for the intergral (int)
i have supported work for 2 * 1/2 int(3 + 2 sin(theta))^2 d theta
am i missing work for the limits?
why am i multiplying by 2?