Heyy i do not understand how to do this?
Find the exact area enclosed between the cureve y = √ 4 - x^2
and the line x - y + 2 = 0
the answer is : ( π - 2 ) units^2
thanks heaps
$\displaystyle \sqrt{4-x^2}$ is the equation of a semicircle, centre (0,0), radius 2,
standing on the x-axis, with maximum point (0,2).
The line y=x+2 intersects this at (-2,0) and (0,2).
Therefore the area between them is
$\displaystyle quarter\ circle\ area-triangle\ area=\frac{\pi(2^2)}{4}-0.5(2)(2)=\pi-2$