hey i do not know how to do this question. I don't know how to simplify the power of 3.

Find the area enclosed between the curve y = x^3 , the x - axis and the line y = -3 x + 4.

the answer is 0.42 units^2.

thank you.

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- Jan 19th 2010, 01:09 AMmaayMaths help for integration
hey i do not know how to do this question. I don't know how to simplify the power of 3.

Find the area enclosed between the curve y = x^3 , the x - axis and the line y = -3 x + 4.

the answer is 0.42 units^2.

thank you. - Jan 19th 2010, 01:28 AMpickslides
You need to find

$\displaystyle

\int_0^ax^3~dx+\int_a^{\frac{4}{3}}-3x+4~dx

$

$\displaystyle a$ is where $\displaystyle x^3 = -3x+4$ - Jan 19th 2010, 02:51 AMmaay
hey i don't get what you mean.

sorry - Jan 19th 2010, 03:17 AMmaay
- Oct 19th 2011, 04:27 AMmr fantasticRe: Maths help for integration