Thread: Integral of the reciprocal Function

Hi guys, its my first post here...hoping you guy can help me solve this problem...


Population Problem: Population of a community is growing at a rate of 5% per year.

DP/DT = .05P

Suppose the population, P, is 1000 at time t=0, and grows to P=N at t=10, where you must fine the value of N. By separating the variables and then integrating you get,

1/p Dp = .05dt

N 10
1 DP = .05dt
p
1000 0


Evaluate the integral numerically for N= 1000, 1500, 2000, 2500, 500, and 100.

Originally Posted by sacsha1

Suppose the population, P, is 1000 at time t=0, and grows to P=N at t=10, where you must fine the value of N. By separating the variables and then integrating you get,

1/p Dp = .05dt

N 10
1 DP = .05dt
p

sacsha1, you did not finish the integration



gives








Now use to find A