antiderivative question

**Baatata** · January 18th 2010, 07:54 PM

for
a. i get:
local max: 2.5*pi
local min: 1.5*pi

b. global max: 3.5pi
global min: 2pi/3

are a and b right?

c. how to do this?

d. by the fundamental theorem of calculas (for this question) g'(x)=f(x) so i will have to find the antiderivative of g'(x).. but whats the antiderivative of xsinx? i dont know how to get it..

**pickslides** · January 18th 2010, 08:06 PM

Originally Posted by Baatata

but whats the antiderivative of xsinx? i dont know how to get it..

you need to employ integration by parts which says

$\int uv' = uv - \int vu'$

in your case make $u = x$ and $v' = \sin(x)$

**VonNemo19** · January 18th 2010, 08:23 PM

Originally Posted by Baatata

for
a. i get:
local max: 2.5*pi
local min: 1.5*pi

b. global max: 3.5pi
global min: 2pi/3

are a and b right?

c. how to do this?

d. by the fundamental theorem of calculas (for this question) g'(x)=f(x) so i will have to find the antiderivative of g'(x).. but whats the antiderivative of xsinx? i dont know how to get it..

It seems to me that $\int_0^xf(t)dt=\int_0^xt\sin{t}dt$ and by parts we have

$g(x)=\int_0^xt\sin{t}dt=-t\cos{t}\Big|_0^x+\int_0^x\cos{t}dt$ . So, now employ the FTC.

**Baatata** · January 18th 2010, 08:30 PM

could you guys break it down for me? i have no idea what you did there..

**pickslides** · January 18th 2010, 08:34 PM

$\int uv' = uv - \int vu'$

in your case make $u = x$ and $v' = \sin(x)$

Go and find

$v = \int \sin(x)$ and $u' = \frac{d}{dx}~x$

Sub these into

$\int uv' = uv - \int vu'$

....

Vonnemo has given you the answer to this in his response.

**Baatata** · January 18th 2010, 08:45 PM

i kinda get it even though i cant figure out how u came up with this forumla

but anyways.. back to the original question, once i found the antiderivative, what do i have to do next?

**pickslides** · January 18th 2010, 08:56 PM

Originally Posted by Baatata

i kinda get it even though i cant figure out how u came up with this forumla

This formula comes from the product rule of differentiation.

Recall

$(uv)' = uv'+vu'$

If you integrate both sides of this equation you get the formula I gave you.

Originally Posted by Baatata

but anyways.. back to the original question, once i found the antiderivative, what do i have to do next?

You sub in the terminals

**Baatata** · January 19th 2010, 08:10 PM

well i just had some help from my friend and he said that i dont even need g(x).

so g'(x) = xsinx.
g'(x) = 0 when x=0,pi, 2pi, 3pi, 4pi
how do i figure out which on is local min/max and global min/max?
i know that when it changes from + to - its local max but what about global max? when would that be?

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