Find the length of the curve from to It says it in the book that 1 + \left(\frac{dx}{dy}\right)^2 is a perfect square but I'm not seeing that. Any help? Edit: I think I found my error. :|
Last edited by VitaX; January 18th 2010 at 07:05 PM.
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The problem starts here g'(y) = y^2 - 1/(4y^2) g' (y) ^2 = y^4 -1/2 + 1/(16y^2) 1 + g' (y)^2 = y^4 +1/2 + 1/(16y^2) = [y^2 +1/(4y^2)]^2
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