# Thread: tangent line

1. ## tangent line

need to find the slope of the tangent line to the curve y=lnx^8 at the point where x=e^2

2. Originally Posted by pebblesbambam
need to find the slope of the tangent line to the curve y=lnx^8 at the point where x=e^2
$\displaystyle y = \ln{x^8}$

$\displaystyle y = 8\ln{x}$

$\displaystyle y' =$ ?

once you determine the derivative, evaluate at $\displaystyle x = e^2$