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Thread: tangent line

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    Question tangent line

    need to find the slope of the tangent line to the curve y=lnx^8 at the point where x=e^2
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    Quote Originally Posted by pebblesbambam View Post
    need to find the slope of the tangent line to the curve y=lnx^8 at the point where x=e^2
    y = \ln{x^8}

    y = 8\ln{x}

    y' = ?

    once you determine the derivative, evaluate at x = e^2
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