1. ## complex polynom

hello, i have to determine the complex zero values of the function z^5+2z^3+z

ok here my try:

z (z^4+2z^2+1) = 0 => gives first zero pt. at 0
now substitution z^4 =u^2 and z^2 = u

now with pq formula i get this: -1+- 0

but what now ??

2. ## Repeated Roots

Let $z^{5}+2z^{3}+z = p(z).$

By the remainder theorem you know that:
$a$ is a root of $p(z) \Leftrightarrow p(z)=(z-a)q(z)$ for some poloynomial $q(z).$
You did this correctly for $a=0$ to get
$p(z) = (z-0)q(z) = z(z^{4}+2z^{2}+1).$
Then by your substitution you found that $u=z^{2}=-1$, hence $z=(-1)^{\frac{1}{2}}=\pm i$, so that we get
$p(z)=z(z^{2}+1)(z^{2}+1) = z(z+i)(z-i)(z+i)(z-i)$.
Therefore the roots are $1,i,-i$. The reason that you got 3 distinct roots instead of the 5 you might expect with an order 5 polynomial is that the factors $(z+i)$ and $(z-i)$ are both repeated in the (unique) factorisation of $p(z).$ So really there are 5 roots, it's just that $i$ and $-i$ are repeated.