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Math Help - Definite Integral Problem with Trig

  1. #1
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    Definite Integral Problem with Trig

    \int^\frac{\pi}{4}_0 \frac{1-sin^2\theta}{cos^2\theta} d\theta

    I have made it this far:

    \int^\frac{\pi}{4}_0 (sec^2\theta) d\theta - \int^\frac{\pi}{4}_0 (tan^2\theta) d\theta

    But I don't know how to integrate tan^2\theta. Am I missing something?

    Thanks!
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  2. #2
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    Quote Originally Posted by seuzy13 View Post
    \int^\frac{\pi}{4}_0 \frac{1-sin^2\theta}{cos^2\theta} d\theta

    I have made it this far:

    \int^\frac{\pi}{4}_0 (sec^2\theta) d\theta - \int^\frac{\pi}{4}_0 (tan^2\theta) d\theta

    But I don't know how to integrate tan^2\theta. Am I missing something?

    Thanks!
    note the basic identity ...

    1-\sin^2{x} = \cos^2{x}
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