# Math Help - Definite Integral Problem with Trig

1. ## Definite Integral Problem with Trig

$\int^\frac{\pi}{4}_0 \frac{1-sin^2\theta}{cos^2\theta} d\theta$

I have made it this far:

$\int^\frac{\pi}{4}_0 (sec^2\theta) d\theta - \int^\frac{\pi}{4}_0 (tan^2\theta) d\theta$

But I don't know how to integrate $tan^2\theta$. Am I missing something?

Thanks!

2. Originally Posted by seuzy13
$\int^\frac{\pi}{4}_0 \frac{1-sin^2\theta}{cos^2\theta} d\theta$

I have made it this far:

$\int^\frac{\pi}{4}_0 (sec^2\theta) d\theta - \int^\frac{\pi}{4}_0 (tan^2\theta) d\theta$

But I don't know how to integrate $tan^2\theta$. Am I missing something?

Thanks!
note the basic identity ...

$1-\sin^2{x} = \cos^2{x}$