I'm trying to figure out this problem. I think I have the answer but I'm not sure.

Find all solutions on the interval [0,2$\displaystyle {\pi} $]. When appropriate put you answer in interval notation.

$\displaystyle cos(x)-\frac{\sqrt{3}}{2}>0 $

1) this is the same as $\displaystyle cos(x)+0>\frac{\sqrt{3}}{2} $ correct?

2) I know that cosx is equal to $\displaystyle \frac{\sqrt{3}}{2} $ at $\displaystyle \frac{\pi}{6},\frac{11\pi}{6} $

but, since it is asking for greater than, I graphed out cosx and thought that the answer is 0, $\displaystyle {2\pi} $. am I close?