
Trig Intervals
I'm trying to figure out this problem. I think I have the answer but I'm not sure.
Find all solutions on the interval [0,2 ]. When appropriate put you answer in interval notation.
1) this is the same as correct?
2) I know that cosx is equal to at
but, since it is asking for greater than, I graphed out cosx and thought that the answer is 0, . am I close?

Hi discobob,
What exactly does the graph of cos(x) look like from 0 to 360 degrees?
It starts at cos(0)=1,
drops to zero at 90 degrees,
goes down to 1 at 180 degrees,
comes back up to zero at 270 degrees,
reaches 1 again at 360 degrees.
Therefore there is an interval from zero to where cos(x) is
where
and similar at the other end of the period.

yes, that is the graph i plotted. I think I dont understand how to figure out the interval where . I can see the area where it is greater than , but i dont know how to define it.

Oh! I think I got it.
Is the answer

Note that you need to solve
