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Thread: Integral

  1. January 18th 2010, 04:28 AM #1
    geriniki
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    Integral

    can u help me by solving this integral
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  2. January 18th 2010, 04:47 AM #2
    earboth
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    Quote Originally Posted by geriniki View Post
    can u help me by solving this integral
    Use integration by substitution:

    Let u(x) = \sin(x) +\cos(x). Then \frac{du}{dx} = \cos(x)-\sin(x)~\implies~du = (-\sin(x) + \cos(x))dx

    Your integral becomes

    \int \left(\frac1{\sqrt{u}}\right) du

    Can you take it from here?
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