I need some help with this:
lim x->0 of ( (3^2x) - 1 ) / ( (3^x) - 1)
The answer should be 2, but I keep getting 0.
I multiply the top and bottom by ( (3^x) + 1) and get this:
((3^3x) + (3^2x) - (3^x) -1) / ((3^2x) + (3^x) - (3^x) - 1)
And so that gives me 0/0.
Any help please? My brain is about to explode.