I need some help with this:

lim x->0 of ( (3^2x) - 1 ) / ( (3^x) - 1)

The answer should be 2, but I keep getting 0.

I multiply the top and bottom by ( (3^x) + 1) and get this:

((3^3x) + (3^2x) - (3^x) -1) / ((3^2x) + (3^x) - (3^x) - 1)

And so that gives me 0/0.

Any help please? My brain is about to explode.