There's an upper limit of 4 and lower limit of 1.
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Originally Posted by Lolcats There's an upper limit of 4 and lower limit of 1. Note that So, can you find ?
Originally Posted by Lolcats There's an upper limit of 4 and lower limit of 1. Hello . Now, . Can you complete it ?
Jeez these are easy problems I'm screwing up. Thanks !
Sorry to be a bother, the answer should be 4 shouldn't it?
Originally Posted by Lolcats Sorry to be a bother, the answer should be 4 shouldn't it? No. See this: integrate [ 2 + 2 x^(-2) ] from x=1 to x=4 - Wolfram|Alpha Please show us your work, to see your mistakes.
Originally Posted by Lolcats Sorry to be a bother, the answer should be 4 shouldn't it? no
K well i'd integrate and get 2x-(2/x), then insert the upper limit so: 2(4) + 2/4 = 4 then minus that from 2(1) + 2/1 = 0 Sorry i'm replying slow I have a seperated shoulder atm and can only type with 1 hand.
Originally Posted by Lolcats K well i'd integrate and get 2x-(2/x), then insert the upper limit so: 2(4) + 2/4 = 4 then minus that from 2(1) + 2/1 = 0 Sorry i'm replying slow I have a seperated shoulder atm and can only type with 1 hand. See the red.
Wops.. thats embarrasing. Thanks again.
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