There's an upper limit of 4 and lower limit of 1.

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- January 17th 2010, 03:42 PMLolcatsAnother Integral Question

There's an upper limit of 4 and lower limit of 1. - January 17th 2010, 03:44 PMVonNemo19
- January 17th 2010, 03:44 PMGeneral
- January 17th 2010, 03:48 PMLolcats
Jeez these are easy problems I'm screwing up. Thanks !

- January 17th 2010, 03:53 PMLolcats
Sorry to be a bother, the answer should be 4 shouldn't it?

- January 17th 2010, 03:55 PMGeneral
No.

See this:

integrate [ 2 + 2 x^(-2) ] from x=1 to x=4 - Wolfram|Alpha

Please show us your work, to see your mistakes. - January 17th 2010, 03:58 PMVonNemo19
- January 17th 2010, 04:02 PMLolcats
K well i'd integrate and get 2x-(2/x), then insert the upper limit so:

2(4) + 2/4 = 4 then minus that from 2(1) + 2/1 = 0

Sorry i'm replying slow I have a seperated shoulder atm and can only type with 1 hand. - January 17th 2010, 04:03 PMGeneral
- January 17th 2010, 04:06 PMLolcats
Wops.. thats embarrasing. Thanks again.