$\displaystyle

\int \frac{{{2x}^2+2}}{x^2}dx

$

There's an upper limit of 4 and lower limit of 1.

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- Jan 17th 2010, 02:42 PMLolcatsAnother Integral Question
$\displaystyle

\int \frac{{{2x}^2+2}}{x^2}dx

$

There's an upper limit of 4 and lower limit of 1. - Jan 17th 2010, 02:44 PMVonNemo19
- Jan 17th 2010, 02:44 PMGeneral
- Jan 17th 2010, 02:48 PMLolcats
Jeez these are easy problems I'm screwing up. Thanks !

- Jan 17th 2010, 02:53 PMLolcats
Sorry to be a bother, the answer should be 4 shouldn't it?

- Jan 17th 2010, 02:55 PMGeneral
No.

See this:

integrate [ 2 + 2 x^(-2) ] from x=1 to x=4 - Wolfram|Alpha

Please show us your work, to see your mistakes. - Jan 17th 2010, 02:58 PMVonNemo19
- Jan 17th 2010, 03:02 PMLolcats
K well i'd integrate and get 2x-(2/x), then insert the upper limit so:

2(4) + 2/4 = 4 then minus that from 2(1) + 2/1 = 0

Sorry i'm replying slow I have a seperated shoulder atm and can only type with 1 hand. - Jan 17th 2010, 03:03 PMGeneral
- Jan 17th 2010, 03:06 PMLolcats
Wops.. thats embarrasing. Thanks again.