in order to do this problem I have I must solve the limit of P(t)=6000-5500e^(-0.159t) as t approaches infinity. I know that the limit is 6000 I just don't know how to show the work to prove this. Please Help!
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$\displaystyle e^{-0.195t}=\frac{1}{e^{0.195t}}$ As t approaches infinity, so does $\displaystyle e^{0.195t}$ hence that part approaches zero.
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