in order to do this problem I have I must solve the limit of

P(t)=6000-5500e^(-0.159t) as t approaches infinity. I know that the limit is 6000 I just don't know how to show the work to prove this. Please Help!

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- Jan 17th 2010, 09:22 AMrawkstarLimit as x approaches infinity
in order to do this problem I have I must solve the limit of

P(t)=6000-5500e^(-0.159t) as t approaches infinity. I know that the limit is 6000 I just don't know how to show the work to prove this. Please Help! - Jan 17th 2010, 09:32 AMArchie Meade
$\displaystyle e^{-0.195t}=\frac{1}{e^{0.195t}}$

As t approaches infinity, so does $\displaystyle e^{0.195t}$

hence that part approaches zero.