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Math Help - Piecewise model

  1. #1
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    Piecewise model

    I have a piecewise model problem that i cannot figure out below is the following problem any help would be appreciated.


    2. Find a piecewise model for the data and graph it together with the original data points. You may want to use a parabola for the points corresponding to the years 1990 - 1994 and a line corresponding to the years 1994 - 1996. Round the coefficients to three decimal places. Does the model provide a good fit for the data points? Explain.



    Below this is all the information for the problem


    Greenhouse Gas Emissions in Australia

    Australia is a relatively small producer of greenhouse gases, accounting for approximately 1.4% of global emissions. However, its emissions per capita rank third amongst industrialized countries. This is due to particular circumstances including an abundance of fossil fuel resources, a dispersed population with a consequent heavy dependence on fossil fuel based transport, and a relatively rapid rate of population growth.

    The following table gives Australia's net greenhouse gas emissions in Mt CO2-e by year. Mt is the abbreviation for megaton, which is one million tons. CO2-e represents carbon dioxide equivalent emissions. CO2 equivalent emissions are calculated by measuring the global warming potential of a greenhouse gas relative to that of CO2. For example, carbon dioxide is assigned a global warming potential (GWP) of 1 and methane a GWP of 21. That is, one ton of methane is equivalent to 21 tons of carbon dioxide in terms of its effect on global warming.



    Year 1990 1991 1992 1993 1994 1995 1996
    Mt CO2-e 384.9 386.1 386.9 389.6 394.2 406.8 419.3
    Source: National Greenhouse Gas Inventory
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  2. #2
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    the parabola for 1990-1994, based on my calculation:
    0.506X^2+0.345X+384.956=Y
    I treated 1990 as year 0.

    for the general solution, someone already posted there.

    http://www.physicsforums.com/showthread.php?t=97382
    Last edited by niva; November 7th 2005 at 10:36 PM.
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  3. #3
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    thanks
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