Solve the differential equation dy/dx= 2y for y given that when x = 1, y = 1 Thanks
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1. separate the variables dy/y = 2dx 2. integrate ln|y| = 2x+ c 3. Apply ICs x= y = 1 0 = 2 + c c=-2 ln|y| = 2x - 2 4. exponentiate y = e^(2x-2) = e^(-2) e^(2x)
Originally Posted by differentiate Solve the differential equation dy/dx= 2y for y given that when x = 1, y = 1 Thanks Method 1: where where . Now letting we find . So . Other possible methods are separation of variables or integrating factor.
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