I am integrating (1/3)(3-x)^-1. Is it (1/3)ln(3-x) ? It probably isn't.
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Originally Posted by Stuck Man I am integrating (1/3)(3-x)^-1. Is it (1/3)ln(3-x) ? It probably isn't. You forgot "-" and "C".
I'm not sure why you put - at the front. 4/x integrates to 4lnx doesn't it?
Originally Posted by Stuck Man I'm not sure why you put - at the front. 4/x integrates to 4lnx doesn't it? yes, but integrates to , because the derivative of is
I see, thanks. Is k sometimes used instead of C?
Originally Posted by Stuck Man I see, thanks. Is k sometimes used instead of C? Not usually but it can be-often with logs. It usually arises when you have the case of because a new constant, k, is introduced such that and
Originally Posted by Stuck Man I see, thanks. Is k sometimes used instead of C? Any letter can be used to represent a constant- as long as you are clear and consistent.
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