You forgot the in your integral.
I think the substitution is better.
Do not forget to change the limits of the integration according to this substitution.
Hi I am in the middle of this question and im not sure if a. im right or b. where to go from here.
Q. Evaluate:
between the limits of 3 and 0
So far I have:
then
when S = 3 then P = 5
and
when S = 0 then P = 4
Am I right so far, if so what is the next step?
thanks
Ok so, a few changes:
then
when S = 3 then u = 5
and
when S = 0 then u = 4
With the limits now between 5 and 4
Ok, that looks a bit better but im still not sure how to take this further, its been ages since ive done anything like this and my mind is blank.
You changed the limits correctly.
The next step is changing your integral to another integral in terms of u according to your substitution.
To do that.
First you should find in terms of
You need to solve your substitution for s then differentiate it with respect to s.
Differentiate with respect to s.
So, For the original integral, we found ds in terms of u.
the denominator is u(Which is just our the substitution you did).
we have s in the numerator.
Actually, we found it above.
You have everything in the original integral in terms of u.
Can you replace them and try to solve the resulting integral ?
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Sir, You are using the substitution method to solve this integral, Right?
I said your substitution will make it hard a little bit.
So, I gave you another substitution to solve it, There is no relation between them.
Show your steps for evaluating the resulting integral which bacame from the substitution.
And also, specify which substitution did you use.
And doubling posts is not allowed in this forum.
For the substitution
and
So the new Upper/Lower limits the integral are 16 and 25.
And we have
i.e.
Integral will be :
.