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Math Help - Stuck on trying to find integral of a mixture of trigonometric functions.

  1. #1
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    Stuck on trying to find integral of a mixture of trigonometric functions.

    Thank so much for all of the help thus far on these problems. This forum has been a life-saver.

    So, I have another one ...

    So, first things first, here is the problem:
    Find the general indefinite integral.

    Here are the steps that I have taken so far:

    My problem is that I still have the second that I havenít dealt with. At this point, I am not sure what to do.
    Any ideas?
    Thank you for your time.
    Regards,
    Christopher K.
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  2. #2
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    If you multiply the orginal integral through the brackets with the sec outside, you have sec squared + sec*tan, split the sum, so tan + sec + c would be the solution?
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  3. #3
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    Quote Originally Posted by matt.qmar View Post
    If you multiply the orginal integral through the brackets with the sec outside, you have sec squared + sec*tan, split the sum, so tan + sec + c would be the solution?

    Is that right?

    Kind of simple I guess but perhaps this is a compressed form of what everything would look like if I used the chain rule on my solution?

    Thanks again.

    Regards,
    Chris K.
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