If you multiply the orginal integral through the brackets with the sec outside, you have sec squared + sec*tan, split the sum, so tan + sec + c would be the solution?
Thank so much for all of the help thus far on these problems. This forum has been a life-saver.
So, I have another one ...
So, first things first, here is the problem:
Find the general indefinite integral.
Here are the steps that I have taken so far:
My problem is that I still have the second that I haven’t dealt with. At this point, I am not sure what to do.
Any ideas?
Thank you for your time.
Regards,
Christopher K.