# Math Help - Stuck on trying to find integral of a mixture of trigonometric functions.

1. ## Stuck on trying to find integral of a mixture of trigonometric functions.

Thank so much for all of the help thus far on these problems. This forum has been a life-saver.

So, I have another one ...

So, first things first, here is the problem:
Find the general indefinite integral.

Here are the steps that I have taken so far:

My problem is that I still have the second that I haven’t dealt with. At this point, I am not sure what to do.
Any ideas?
Regards,
Christopher K.

2. If you multiply the orginal integral through the brackets with the sec outside, you have sec squared + sec*tan, split the sum, so tan + sec + c would be the solution?

3. Originally Posted by matt.qmar
If you multiply the orginal integral through the brackets with the sec outside, you have sec squared + sec*tan, split the sum, so tan + sec + c would be the solution?

Is that right?

Kind of simple I guess but perhaps this is a compressed form of what everything would look like if I used the chain rule on my solution?

Thanks again.

Regards,
Chris K.