y=-2x+3
on integration we get RHS as
=-2((x^2)/2)+3x +c
=3x-x^2+c
now put limits from 0 to 1
so area obtained will be
=3(1)-1+c-[3(0)-0+c]
=3-1
=2 sq.units
The equation is y=-2x+3 and the points are [0,1]
i simplified and got
lim n as it approaches infiniy of
-2/n^2 * n(n+1)/2 + 3/n *n
the answer is supposed to be 2 but i dont understand how to get the limits to equal 2. I cant get all the n to cancel out