Thanks. This is useful.
Last edited by AlphaRock; January 13th 2010 at 02:13 PM.
Follow Math Help Forum on Facebook and Google+
It is given as Riemann sum.
The subintervals are
The integral is:
On top of what the last poster offered, this is what I wrote up (and forgot to send a long time ago because I got enormously side-tracked):
Let be the right-hand endpoint of the subinterval; i.e., , for
Thus, , , and
And we have:
View Tag Cloud