Thanks. This is useful.
Last edited by AlphaRock; Jan 13th 2010 at 01:13 PM.
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It is given as Riemann sum.
The subintervals are
The integral is:
On top of what the last poster offered, this is what I wrote up (and forgot to send a long time ago because I got enormously side-tracked):
Let be the right-hand endpoint of the subinterval; i.e., , for
Thus, , , and
And we have:
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