Find the limit lim x-> infinity [1/x] / [1/3 x ^(-2/3)] First, I do not understand how I get to the simplyfied term: lim x-> infinity 3 / x^1/3 Second, I do not understand why the answer is zero. Thanks
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Originally Posted by DBA Find the limit lim x-> infinity [1/x] / [1/3 x ^(-2/3)] First, I do not understand how I get to the simplyfied term: lim x-> infinity 3 / x^1/3 Second, I do not understand why the answer is zero. Thanks remember how to divide fractions? now ... what happens to the value as x gets very large?
Yes remember 3x^3/3-2/3 = 3x^1/3 Thanks, I got that now. lim x->infinity 3/x^1/3 = 0 the nominator stays 3 and the denominator gets larger and larger. So, the entire term gets smaller and smaller. Thus closer and closer to zero. Thanks!
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