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Math Help - Differentiation

  1. #1
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    Differentiation

    Could someone help with this problem, let me know if I am correct. Thanks


    Y = [(AL)1/2 +BK1/2]2
    dY/dK = [1 +BK1/2]2
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  2. #2
    MHF Contributor Calculus26's Avatar
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    Y = [(AL)1/2 +BK1/2]2

    Assuming A,L and B are comstants

    Think of this as Y = u^2 where u = [(AL)^(1/2) + BK^(1/2)]

    dy/dk = 2u du/dk = 2[(AL)^(1/2) + BK^(1/2)] *(1/2BK^(-1/2))
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