Rotating around x and y axis

**Jones** · January 12th 2010, 09:22 AM

Hi,

I have a problem i wasn't able to solve, i don't know how to calculate the volume of the generated body, when it is rotated around both the x and the y axis.

$A = \{(x,y):\sqrt{x}e^{x^2}~\le y \le 3,~ 0 \le x \le 1 \}$

Jones

**earboth** · January 12th 2010, 10:21 AM

Originally Posted by Jones

Hi,

I have a problem i wasn't able to solve, i don't know how to calculate the volume of the generated body, when it is rotated around both the x and the y axis.

$A = \{(x,y):\sqrt{x}e^{x^2}~\le y \le 3,~ 0 \le x \le 1 \}$

Jones

I can show you how to calculate the volume when the curve rotates about the x-axis.

The general formula for a rotation volume with the x-axis as axis of rotation is:

$V_{rotx} = \pi\int_a^b y^2 dx$

Plug in the terms you know:

$V_{rotx}=\pi \int_0^1\left(\sqrt{x} \cdot e^{x^2} \right)^2 dx$

$V_{rotx}=\pi \int_0^1\left(x \cdot e^{2x^2} \right) dx$

Now use integration by substitution:

$u = 2x^2~\implies~\frac{du}{dx} = 4x~\implies~du = 4x dx$

The integral becomes:

$V_{rotx}=\frac{\pi}{4} \int_0^1\left(4x \cdot e^{2x^2} \right) dx$

$V_{rotx}=\frac{\pi}{4} \int_0^1\left( e^{u} \right) du$

Can you take it from here?

-----------------------------------------------------------------------

There is missing at least one value to calculate the rotation volume if the y-axis is the axis of rotation.

**Jones** · January 12th 2010, 11:16 AM

Originally Posted by earboth

I can show you how to calculate the volume when the curve rotates about the x-axis.

Can you take it from here?

-----------------------------------------------------------------------

There is missing at least one value to calculate the rotation volume if the y-axis is the axis of rotation.

?? You already did it for me. The only thing remaining is to plug in the limits.

And what value is missing?, this question should be solvable

**earboth** · January 12th 2010, 10:29 PM

Originally Posted by Jones

?? You already did it for me. The only thing remaining is to plug in the limits.

And what value is missing?, this question should be solvable

I've had some difficulties to understand this line:

$A = \{(x,y):\sqrt{x}e^{x^2}~\le y \le 3,~ 0 \le x \le 1 \}$

If you mean

$y = f(x)= \sqrt{x} \cdot e^{x^2}\ ,\ 0\leq x \leq 1$

then the property $y \leq 3$ is unnecessary because f(1) = e < 3.

-----------------------------------------------

To calculate the rotation volume with the y-axis as axis of rotation you have to use the general equation:

$V_{roty} = \int_a^b \pi \cdot x^2 dy$

Since $\frac{dy}{dx} = y'~\implies~dy = y' \cdot dx$

this equation becomes:

$V_{roty} = \int_a^b \pi \cdot x^2 y' \cdot dx$

But unfortunately the integrand becomes very ugly so I can only provide you with an approximative result: $V_{roty} \approx 3.994$

Thread: Rotating around x and y axis

LinkBack

Thread Tools

Display

Rotating around x and y axis

Similar Math Help Forum Discussions

rotating a solid about the y axis

Volume that results from rotating about the X axis

find the volume by rotating about x-axis

Conics- Rotating The Axis

Volume by rotating the y axis

Search Tags