Lim e^(x-y)
(x,y)->(0,ln2)
so
e^(0-ln2) = e^(-ln2)
ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?
Thanks
Lim e^(x-y)
(x,y)->(0,ln2)
so
e^(0-ln2) = e^(-ln2)
ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?
Thanks