# Math Help - Multivariable Limits

1. ## Multivariable Limits

Lim e^(x-y)
(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?
Thanks

2. Originally Posted by ur5pointos2slo
Lim e^(x-y)
(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?
Thanks
$e^{-\ln(2)}=e^{\ln\left(\tfrac{1}{2}\right)}=\frac{1}{ 2}$