Lim e^(x-y)

(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?

Thanks

Printable View

- Jan 12th 2010, 07:46 AMur5pointos2sloMultivariable Limits
Lim e^(x-y)

(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?

Thanks - Jan 12th 2010, 07:48 AMDrexel28