# Multivariable Limits

• January 12th 2010, 07:46 AM
ur5pointos2slo
Multivariable Limits
Lim e^(x-y)
(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?
Thanks
• January 12th 2010, 07:48 AM
Drexel28
Quote:

Originally Posted by ur5pointos2slo
Lim e^(x-y)
(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?
Thanks

$e^{-\ln(2)}=e^{\ln\left(\tfrac{1}{2}\right)}=\frac{1}{ 2}$