Lim e^(x-y)

(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?

Thanks

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- Jan 12th 2010, 08:46 AMur5pointos2sloMultivariable Limits
Lim e^(x-y)

(x,y)->(0,ln2)

so

e^(0-ln2) = e^(-ln2)

ok so I would just think the e and ln would cancel each other and the answer be -2 but that isn't the case. The correct answer is 1/2. Can anyone please show me where this came from?

Thanks - Jan 12th 2010, 08:48 AMDrexel28