= 4 ( 1/ (x^2 - 2x)) = 4 ( 1/ 1- (1-x)^2)
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Originally Posted by harveyo = 4 ( 1/ (x^2 - 2x)) = 4 ( 1/ 1- (1-x)^2) More context needed. Also: should give a series expansion for and CB
Context: write the power series expansion, indicate an interval of convergence when center c = 1
Okay well, in order to do that, I'll give you an example: We have then put and you'll get the series centered at
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