Thread: power series expansion II

= 4 ( 1/ (x^2 - 2x))

= 4 ( 1/ 1- (1-x)^2)

Originally Posted by harveyo

= 4 ( 1/ (x^2 - 2x))

= 4 ( 1/ 1- (1-x)^2)

More context needed.

Also:



should give a series expansion for and

CB

Context: write the power series expansion, indicate an interval of convergence when center c = 1

Okay well, in order to do that, I'll give you an example:

We have then put and you'll get the series centered at