= 4 ( 1/ (x^2 - 2x))

= 4 ( 1/ 1- (1-x)^2)

Printable View

- Jan 11th 2010, 09:24 PMharveyopower series expansion II

= 4 ( 1/ (x^2 - 2x))

= 4 ( 1/ 1- (1-x)^2) - Jan 11th 2010, 10:46 PMCaptainBlack
- Jan 12th 2010, 03:06 AMharveyo
Context: write the power series expansion, indicate an interval of convergence when center c = 1

- Jan 12th 2010, 04:42 AMKrizalid
Okay well, in order to do that, I'll give you an example:

We have then put and you'll get the series centered at