I have that f(x)= 4x-x^2 and g(x)= x^2 - 6x + 8 I just want to know which one is bigger than the other one. Since both are parabolas: one facing down, the other one up .. should I just say that f(x) is bigger since its on top?
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Depends on what interval for x you are trying to find the area for. Do you know? This is for "under the curve" or are you trying to find area between the curves?
sorry, you are right. It's the are between the curves. The graph gives me the interval [1,4].
Interval looks fine, $\displaystyle \int_{1}^4 \left(f(x)- g(x)\right) ~dx$ $\displaystyle \int_{1}^4 \left((4x-x^2)-( x^2 - 6x + 8)\right) ~dx$
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