Question: If $\displaystyle y = x^x$ find the relative rate of change of y with respect to x when x = 1. How do I go about answering this question?
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You derive the equation, the derivate is the relative rate of change.
oh thats it! thank you so much Answer would be: $\displaystyle X^x (ln x + 1)$ correct?
Ops! I saw x^2 how do you bla bla, at first I though what kind of question is that to post here....Now I realize I´m the idiot sorry........
deregard
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