Question: If $\displaystyle y = x^x$ find the relative rate of change of y with respect to x when x = 1.

How do I go about answering this question?

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- Jan 11th 2010, 01:50 PMbearhugrelative rate of change
Question: If $\displaystyle y = x^x$ find the relative rate of change of y with respect to x when x = 1.

How do I go about answering this question? - Jan 11th 2010, 02:04 PMHenryt999You derive
You derive the equation, the derivate is the relative rate of change.

- Jan 11th 2010, 02:11 PMbearhug
oh thats it! thank you so much

Answer would be: $\displaystyle X^x (ln x + 1)$ correct? - Jan 11th 2010, 02:17 PMHenryt999Ohh sorry
Ops!

I saw x^2 how do you bla bla, at first I though what kind of question is that to post here....Now I realize I´m the idiot sorry........ - Jan 11th 2010, 02:19 PMbigwave
deregard