how do you find the volume of the solid generated by revolving btw the x axis and y= 4x - x^2 about the line y=6.
the volume required is not bounded btw the line y= 6 and the eqn and hence i am stuck..
thanks!
the point of intersection with the x-axis is x= 0 and x=4.
what i did was
find the volume of the cylinder of radius 4, height 6 - (pi) integrate (6-y)^2
= pi( 96) - pi integrate ( 6- 4x + x^2)^2
but i could not get the answer.
should it not be 6- y for the second part of my equation?