When you integrate 2sin$\displaystyle x$cos$\displaystyle x$$\displaystyle /$1-2$\displaystyle (cosx)^2$is the answer $\displaystyle -$$\displaystyle (sec2x)^2$/2? If not, then what would be the proper approach?
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What about substituting $\displaystyle u=1-2cos^{2}(x)$ and trying to answer your question by yourself?
I get 1/2ln(1-2cos^2x)+c. Is that right?
Originally Posted by bhuang I get 1/2ln(1-2cos^2x)+c. Is that right? Does it work when you differentiate it?
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